Question #39463

. Show that 90 J of work is needed to increase the speed of
a 20-kg cart by 3 m/s.

Expert's answer

Answer on Question #39463, Physics, Mechanics | Kinematics | Dynamics

Show that 90 J of work is needed to increase the speed of a 20-kg cart by 3 m/s.

**Solution:**

In order to accomplish work on an object there must be a force exerted on the object and it must move in the direction of the force.

Work = Force x distance moved in direction of force


W=FdW = F \cdot d


Newton's Second Law


F=maF = m a


Kinematics equation


2ad=v2v022 a d = v ^ {2} - v _ {0} ^ {2}


where aa is acceleration, dd is distance, v0v_{0} is initial velocity and vv is final velocity.

Thus,


W=Fd=mad=m2(v2v02)W = F \cdot d = m a d = \frac {m}{2} (v ^ {2} - v _ {0} ^ {2})


When v0=0,vv0=Δv=3m/sv_{0} = 0, v - v_{0} = \Delta v = 3 \, \text{m/s}

v2v02=(v+v0)(vv0)=ΔvΔv=(Δv)2v ^ {2} - v _ {0} ^ {2} = (v + v _ {0}) (v - v _ {0}) = \Delta v \cdot \Delta v = (\Delta v) ^ {2}


Thus,


W=m2(v2v02)=m(Δv)22=20(3)22=90JW = \frac {m}{2} (v ^ {2} - v _ {0} ^ {2}) = \frac {m (\Delta v) ^ {2}}{2} = \frac {2 0 \cdot (3) ^ {2}}{2} = 9 0 \, \text{J}

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