Question

A glass with a mass of 0.472 kg is dropped and has a speed of 2.7 m/s when it suddenly hits the hard dining room floor. Calculate the impulse force

Answer 1

Answer on Question#39371 – Physics - Other

A glass with a mass of $0.472\ \mathrm{kg}$ is dropped and has a speed of $2.7\ \mathrm{m/s}$ when it suddenly hits the hard dining room floor. Calculate the impulse force

Solution:

The impulse of force can be extracted and found to be equal to the change in momentum of an object provided the mass is constant:

$$\text{Impulse} = F\Delta t = m\Delta v = 0.472\ \mathrm{kg} \cdot 2.7\ \frac{\mathrm{m}}{\mathrm{s}} = 1.27\ \mathrm{kg}\ \frac{\mathrm{m}}{\mathrm{s}}$$

Answer: impulse of force is equal to $1.27\ \mathrm{kg}\ \frac{\mathrm{m}}{\mathrm{s}}$.