Question

A ball dropped from the height of of 200
meters how much time or when it will take to
hit the surface? and what will be the final
velocity"

Answer 1

Answer on Question#39333 – Physics – Mechanics

A ball dropped from the height of 200 meters how much time or when it will take to hit the surface? And what will be the final velocity"

Solution:

The equation of motion for the ball relative to the Y-axis (vertical axis):

$$\mathrm{H} = \frac{\mathrm{gt}^2}{2}; \quad (\mathrm{V}_{\mathrm{start}} = 0)$$ $$t = \sqrt{\frac{2\mathrm{H}}{\mathrm{g}}} = \sqrt{\frac{2 \cdot 200\,\mathrm{m}}{9.8\,\frac{\mathrm{m}}{\mathrm{s}^2}}} = 6.4\,\mathrm{s}$$

The rate equation for the ball before hitting the surface:

$$V = gt = 9.8\,\frac{\mathrm{m}}{\mathrm{s}^2} \cdot 6.4\,\mathrm{s} = 63\,\frac{\mathrm{m}}{\mathrm{s}}$$

Answer: after 6.4 s ball will hit the ground, final velocity $63\,\frac{\mathrm{m}}{\mathrm{s}}$