Question

A 3oo kg sailboat accelerates at 0.5 m/s2 at angle 25 degrees N of E, find the magnitude and direction of the force responsible for this acceleration

Answer 1

Answer on Question #39305, Physics, Mechanics | Kinematics | Dynamics

A 300 kg sailboat accelerates at 0.5 m/s² at angle 25 degrees N of E, find the magnitude and direction of the force responsible for this acceleration

Solution:

Given:

$$m = 300 \text{ kg}$$ $$a = 0.5 \text{ m/s}^2$$

The magnitude of force is equated to the product of the mass times the acceleration.

$$F = m a = 300 \cdot 0.5 = 150 \text{ N}$$

The direction of force is 25 degrees N of E.

Answer. $F = 150 \text{ N}$, the direction of force is 25 degrees N of E.