Question #39107

A 54.8-kg baseball pitching machine is placed on a frozen pond. It fires a 0.133-kg baseball at an angle of 30 degrees with the vertical at a speed of 18.5 m/s. What is the recoil velocity (in cm/s) of the machine?

Expert's answer

Answer on Question #39107, Physics, Mechanics

Question:

A 54.8-kg baseball pitching machine is placed on a frozen pond. It fires a 0.133-kg baseball at an angle of 30 degrees with the vertical at a speed of 18.5 m/s. What is the recoil velocity (in cm/s) of the machine?

Answer:

The law of conservation of momentum:


mvx=Mum v _ {x} = M u


where mm is baseball's mass, MM mass of pitching machine, uu is the recoil velocity:


vx=vsin30=v2v _ {x} = v \sin 3 0 = \frac {v}{2}


Therefore the recoil velocity equals:


u=mvxM=0.13318.5254.8=22.4cmsu = \frac {m v _ {x}}{M} = \frac {0 . 1 3 3 * 1 8 . 5}{2 * 5 4 . 8} = 2 2. 4 \frac {c m}{s}


Answer: 22.4cms22.4\frac{cm}{s}

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