Question

a particle of mass m and carrying charge -q1 starts moving around q2 along a circular path of radius r. what is period of revolution?

Answer 1

Answer on Question #39009, Physics, Mechanics

Question:

A particle of mass m and carrying charge -q1 starts moving around q2 along a circular path of radius r. what is period of revolution?

Answer:

Newton's second law of motion:

$$\frac{m v^{2}}{r} = \frac{k q_{1} q_{2}}{r^{2}}$$

where $\frac{v^{2}}{r}$ is centripetal acceleration, $\frac{k q_{1} q_{2}}{r^{2}}$ is Coulomb's force.

Therefore, speed of motion equals:

$$v = \sqrt{\frac{k q_{1} q_{2}}{m r}}$$

Period equals:

$$T = \frac{2 \pi r}{v} = 2 \pi r \sqrt{\frac{m r}{k q_{1} q_{2}}}$$

Answer: $T = 2 \pi r \sqrt{\frac{m r}{k q_{1} q_{2}}}$