Question #38882

What is the hang time of a rocket that is launched at an angle of 45 degrees with a launch velocity of 60m/s?

Expert's answer

Answer on Question #38882, Physics, Mechanics

Question:

What is the hang time of a rocket that is launched at an angle of 45 degrees with a launch velocity of 60m/s?

Answer:

Height for uniformly accelerated motion equals:


h=v0sinαtgt22h = v _ {0} \sin \alpha * t - \frac {g t ^ {2}}{2}


where v0v_{0} - initial velocity of the ball, gg - gravitational acceleration, tt - time.

Time when height equals 0:


v0sinαtgt22=0v _ {0} \sin \alpha * t - \frac {g t ^ {2}}{2} = 0t=2v0sinαg=8.7st = \frac {2 v _ {0} \sin \alpha}{g} = 8.7 \, \text{s}


Answer: 8.7 s

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