Question

determine x and y:
A 31-m/s velocity vector that makes an angle of 44° counterclockwise from the -x direction.
x:
y:

Answer 1

Answer on Question#38854 – Physics – Other

determine x and y:

A 31-m/s velocity vector that makes an angle of $44{}^{\circ}$ counterclockwise from the -x direction. x: y:

Solution:

Projection of the velocity vector on the X-axis:

$$V_x = V \cdot \cos 44{}^{\circ} = 31 \frac{\mathrm{m}}{\mathrm{s}} \cdot \cos 44{}^{\circ} = 22.3 \frac{\mathrm{m}}{\mathrm{s}}$$

Projection of the velocity vector on the X-axis:

$$V_y = V \cdot \sin 44{}^{\circ} = 31 \frac{\mathrm{m}}{\mathrm{s}} \cdot \sin 44{}^{\circ} = 21.5 \frac{\mathrm{m}}{\mathrm{s}}$$

Answer: x: $22.3 \frac{\mathrm{m}}{\mathrm{s}}$

y: $21.5 \frac{\mathrm{m}}{\mathrm{s}}$