Question #38796

What will be the resultant speed of a boat whose heading is 60 degrees with respect to the current and whose speed is 15 km/hr with respect to the water if the current has a speed of 2.0 km/hr and the wind is blowing in a direction of 20 degrees to the current with a speed of 5.0 km/hr?

Expert's answer

Answer on Question #38796, Physics, Mechanics

Question:

What will be the resultant speed of a boat whose heading is 60 degrees with respect to the current and whose speed is 15 km/hr with respect to the water if the current has a speed of 2.0 km/hr and the wind is blowing in a direction of 20 degrees to the current with a speed of 5.0 km/hr?

Answer:

Component directed along current equals:


v1=2kmh+15cos60kmh+5cos20kmh=14.2kmhv_1 = 2 \frac{km}{h} + 15 * \cos 60{}^\circ \frac{km}{h} + 5 * \cos 20{}^\circ \frac{km}{h} = 14.2 \frac{km}{h}


Component directed perpendicular to the current equals:


v2=15sin60kmh+5sin20kmh=14.7kmhv_2 = 15 * \sin 60{}^\circ \frac{km}{h} + 5 * \sin 20{}^\circ \frac{km}{h} = 14.7 \frac{km}{h}


Therefore resultant speed of a boat equals:


v=v12+v22=20.4kmhv = \sqrt{v_1^2 + v_2^2} = 20.4 \frac{km}{h}


Answer: 20.4 kmh\frac{km}{h}

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