Question

If you drop an aspirin and it takes 0.18 sec to hit the table, how high above the table was the aspirin when it was released?

Answer 1

Answer on Question #38530, Physics, Mechanics | Kinematics | Dynamics

Question:

If you drop an aspirin and it takes 0.18 sec to hit the table, how high above the table was the aspirin when it was released?

Answer:

Aspirin moves with acceleration due to gravity with initial speed 0, therefore height equals:

$$h = \frac {g t ^ {2}}{2}$$

where $g$ is acceleration due to gravity, $t$ – time

$$h = \frac {1}{2} 9.81 \frac {m}{s ^ {2}} * (0.18s) ^ {2} = 0.16 \, m$$

Answer: $0.16 \, m$