Question #38500

Calculate tension(centripetal force) of the rope with a stone at its end. Mass of the stone is 2 kg, length of the rope is 5 m, the stone velocity is 10 m/2

Expert's answer

Answer on Question#38500 – Physics - Mechanics | Kinematics | Dynamics

Calculate tension(centripetal force) of the rope with a stone at its end. Mass of the stone is 2kg2\mathrm{kg}, length of the rope is 5m5\mathrm{m}, the stone velocity is 10m/210\mathrm{m}/2

Solution:

m=2kg\mathrm{m} = 2\mathrm{kg} – mass of the stone;

l=5ml = 5\mathrm{m} – length of the rope;

V=10msV = 10\frac{\mathrm{m}}{\mathrm{s}}

Formula for the centripetal force:


F=mac=mV2l=2kg(10ms)25m=40NF = m a _ {c} = m \frac {V ^ {2}}{l} = 2 k g \cdot \frac {\left(1 0 \frac {m}{s}\right) ^ {2}}{5 m} = 4 0 N


Answer: centripetal force of the rope is equal to 40N.

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