Question #38486

A plane with a speed of 75m/s is going to travel along a runway of 25km, If it makes an acceleration of 1.3(m/s)/s, will it use the runway safely? Justify your answer.

Expert's answer

Answer on Question#38486 – Physics – Mechanics | Kinematics | Dynamics

A plane with a speed of 75m/s75\,\mathrm{m/s} is going to travel along a runway of 25km25\,\mathrm{km}. If it makes an acceleration of 1.3m/s/s1.3\,\mathrm{m/s/s}, will it use the runway safely? Justify your answer.

Solution:

a=1.3ms2decceleration of the plane;a = 1.3\,\frac{\mathrm{m}}{\mathrm{s}^2} - \text{decceleration of the plane};V0=75msinitial velocity of the plane;V_0 = 75\,\frac{\mathrm{m}}{\mathrm{s}} - \text{initial velocity of the plane};


Equation of motion for the plane for first distance dd:


d=V0tat22d = V_0 t - \frac{a t^2}{2}


Rate equation for the plane for this distance (V1=0V_1 = 0 – velocity after time tt):


V1=V0atV_1 = V_0 - a tV0at=0V_0 - a t = 0t=V0at = \frac{V_0}{a}


(2)in(1):


d=V0V0aa(V0a)22=V022a=(75ms)221.3ms2=2160md = V_0 \cdot \frac{V_0}{a} - \frac{a \left(\frac{V_0}{a}\right)^2}{2} = \frac{V_0^2}{2a} = \frac{(75\,\frac{\mathrm{m}}{\mathrm{s}})^2}{2 \cdot 1.3\,\frac{\mathrm{m}}{\mathrm{s}^2}} = 2160\,\mathrm{m}


Answer: plane will use the runway safely (travelled distance 2.16km<25km2.16\,\mathrm{km} < 25\,\mathrm{km}).

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