Question #38461

1. A cyclist is riding on a road, at a uniform speed of 5 m/s for 2 hours. What is his acceleration?

Expert's answer

Answer on Question#38461 – Physics - Mechanics

A cyclist is riding on a road, at a uniform speed of 5 m/s for 2 hours. What is his acceleration?

Solution:


v=5msuniform speed of the cyclist.v = 5 \frac{m}{s} - \text{uniform speed of the cyclist}.t=2 hour=7200stime.t = 2 \text{ hour} = 7200 \text{s} - \text{time}.


Travelled distance:


S=vt=2πRS = v \cdot t = 2\pi RR=vt2πR = \frac{vt}{2\pi}


From the definition of the centripetal acceleration, thus:


ac=v2R=2πv2vt=2πvt=2π5ms7200s=0.004ms2a_c = \frac{v^2}{R} = \frac{2\pi v^2}{vt} = \frac{2\pi v}{t} = \frac{2\pi \cdot 5 \frac{m}{s}}{7200 \text{s}} = 0.004 \frac{m}{s^2}


Answer: centripetal acceleration is equal to 0.004ms20.004 \frac{m}{s^2}.

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