Question

An object is thrown horizontally from a height of 20 m with velocity 10 m s-1. Find its velocity after 1s
(g = 10 m s-2 )

Answer 1

Answer on Question 38283, Mechanics, Kinematics, Dynamics Let us write down the equation for vertical velocity

$v_{y}=-gt$

the horizontal velocity is constant, $v_{x}=v_{x0}=const$. Hence, total velocity after 1 second is

$v=\sqrt{v_{x}^{2}+v_{y}^{2}}=\sqrt{(gt)^{2}+v_{x0}^{2}}=\sqrt{10+10}=\sqrt{20}\approx 4.47\,m/s$