Question #37874

what is the displacment of object performing simple harmonic motion when kinetic and potiential energy are equal?

Expert's answer

Answer on Question#37874, Physics, Other

Question:

what is the displacement of object performing simple harmonic motion when kinetic and potential energy are equal?

Answer:

Let us consider a harmonic oscillator with total energy which is the sum of kinetic energy TT and potential energy UU:


E=T+UE = T + U


or


E=mv22+kx22E = \frac{m v^{2}}{2} + \frac{k x^{2}}{2}


where mm – is a mass of the object, vv – its velocity, xx – its displacement, kk – a coefficient characterizing the system.

If at some moment of time the kinetic energy TT is equal to potential energy UU then the displacement of the object is


x=mv2kx = \sqrt{\frac{m v^{2}}{k}}


or


x=2Tk=Ekx = \sqrt{\frac{2 T}{k}} = \sqrt{\frac{E}{k}}

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