water flows at a speed 5cm /s through a pipe of radius 2cm ,the viscosity of water is 0.001 pl .the reynolds number and the nature of flow are respectively ?????????????????/
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Expert's answer
2013-11-27T02:13:34-0500
Reynolds number can be found as:
R= v*L/nu
where v is speed of water, L is characteristic linear dimension (diameter in our case = 4 cm) and nu is viscosity. Thus we find
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