Question #37309

a large vessel of height H ,is filled with a liquid of density D ,upto the brim .a small hole of radius r is made at the side verticle face ,close to the base .the horizontal force is required to stop the gushing of liquid ??????????????????

Expert's answer

A large vessel of height HH, is filled with a liquid of density DD, up to the brim. A small hole of radius rr is made at the side vertical face, close to the base. The horizontal force is required to stop the gushing of liquid?

Force equals:


F=pSF = pS


where pp – pressure, SS – area of the hole.

The pressure of liquid at the height HH equals:


p=DgHp = DgH


where DD – density of liquid, gg – acceleration due to gravity

Area of the hole equals:


S=πr2S = \pi r^2


Therefore:


F=DgHπr2F = DgH\pi r^2


Answer: F=DgHπr2F = DgH\pi r^2

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