Question #37259

The kinetic energy of an 1800-kg truck is 7.2 × 105 J. What is the speed of the truck?

Expert's answer

The kinetic energy of an 1800-kg truck is 7.2×1057.2 \times 105 J. What is the speed of the truck?

The kinetic energy of the body equals:


T=mv22T = \frac{m v^{2}}{2}


where mm - mass of the body, vv - speed of the body.

Therefore, speed equals:


2Tm=v2\frac{2T}{m} = v^{2}v=2Tm=27.2105J1800kg=28msv = \sqrt{\frac{2T}{m}} = \sqrt{\frac{2 * 7.2 * 10^{5} J}{1800 \, kg}} = 28 \, \frac{m}{s}


Answer: 28ms28 \, \frac{m}{s}

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