Question

A 60.0-kg man is riding an escalator in a shopping mall. The escalator moves the man at a constant velocity from ground level to the floor above, a vertical height of 3.70 m. What is the work done on the man by (a) the gravitational force and (b) the escalator?

Answer 1

b. work done by escalator:
A = mgh = 60*9.8*3.7 = 2175.6 J

a.work done by gravitational force is modulo equal and opposite sign to that of escalator
A=-2175.6 J