Question #37146

A vertical U tube of uniform cross-section contains water in both the arms .A 10cm glycerine column (R.D=1.2)is added to one of the limbs .the level difference b/w the two free surface in the two limbs will be ????????????????????????????????????????

Expert's answer

A vertical U tube of uniform cross-section contains water in both the arms. A 10cm glycerin column (R.D=1.2) is added to one of the limbs. The level difference b/w the two free surface in the two limbs will be?

**Solution:**

hh=10cm=0.1mh_h = 10 \, \text{cm} = 0.1 \, \text{m} - hight of the glycerin in first arm;

hwh_w - hight of the water in second arm;

ρw=1000kgm3\rho_w = 1000 \frac{\mathrm{kg}}{\mathrm{m}^3} - density of the water;

ρh=1200kgm3\rho_h = 1200 \frac{\mathrm{kg}}{\mathrm{m}^3} - density of the glycerin;

x - level difference b/w the two free surface in the two limbs;

Pressures at level AA' of the water and glycerin are equal:

AA:pw=phAA^{\prime}:p_w = p_h

ρhghh=ρwghw\rho_hgh_h = \rho_wgh_w (1)

hw=hh+xh_w = h_h + x (2)

(2)in(1):

ρhghh=ρwg(hh+x)\rho_hgh_h = \rho_wg(h_h + x)

ρhhh=ρwhh+ρwx\rho_h h_h = \rho_w h_h + \rho_w x

x=ρhhhρwhhρw=0.1m(1200kgm31000kgm3)1000kgm3=0.02m=2cmx = \frac {\rho_ {h} h _ {h} - \rho_ {w} h _ {h}}{\rho_ {w}} = \frac {0 . 1 m \left(1 2 0 0 \frac {k g}{m ^ {3}} - 1 0 0 0 \frac {k g}{m ^ {3}}\right)}{1 0 0 0 \frac {k g}{m ^ {3}}} = 0. 0 2 m = 2 c m


**Answer:** the level difference b/w the two free surface in the two limbs will be 2cm.


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