A Spring balance reads 200gF WHEN CARRYING A Lump of lead in air .if the lead is now immersed with half of its volume in brine solution ,what will be the new reading of the spring balance specfic gravity of lead and brine are 11.4 and 1.1 respectively ............???????????????
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Comments
the answer is wrong. As the vol is.half the formula will be = m(1-d÷2d')