Question

A 214-kg crate is pushed horizontally with a force of 719 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.

Answer 1

A 214-kg crate is pushed horizontally with a force of 719 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.

$F_{fr}$ - friction force

$F$ - pulling force

Newton's second law of motion:

$$x: F - F _ {f r} = m a$$ $$y: N = m g$$

Friction force equals $F_{fr} = \mu N = \mu mg$ , $\mu$ - coefficient of friction.

Therefore:

$$a = \frac {F - \mu m g}{m} = \frac {7 1 9 N - 2 1 4 * 9 . 8 * 0 . 2 N}{2 1 4 k g} = 1. 4 \frac {m}{s ^ {2}}$$

Answer: $1.4\frac{m}{s^2}$