Question #36863

A 5kg pumpkin is dropped from the roof of the school. If the school is 10 m tall, what is the final velocity of the pumpkin when it hits the ground? (if something is just dropped, what is its initial velocity? Acceleration due to gravity = 9.81 m/s2

Expert's answer

A 5kg pumpkin is dropped from the roof of the school. If the school is 10 m tall, what is the final velocity of the pumpkin when it hits the ground? (if something is just dropped, what is its initial velocity? Acceleration due to gravity = 9.81 m/s²

The law of conservation of energy:


T+U=constT + U = \text{const}

T=mv22T = \frac{mv^2}{2} - kinetic energy, m - mass of the body, v - speed

U=mghU = mgh - potential energy, g - gravitational acceleration, h - high

If pumpkin is just dropped, v0=0v_0 = 0

0+mgh=mv2/2+00 + mgh = m v^2 / 2 + 0v=2gh=29.81ms210m=14.0msv = \sqrt{2gh} = \sqrt{2 * 9.81 \frac{m}{s^2} \cdot 10 \, m} = 14.0 \, \frac{\mathrm{m}}{\mathrm{s}}


Answer: 14.0ms14.0 \, \frac{\mathrm{m}}{\mathrm{s}}

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