Question

The earth (mass =6 into 10 raise to power 24 kg)revoives around the sun with an angular velocity of 2 into 10 raise to power minus 7 rad/s in circular orbit of radius 1.5 into 10 raise to power 8 km .the fore exertedby the sun on earth in newtons is............................................?????????????????????//

Answer 1

1. The earth (mass = $6 \cdot 10^{24} \, \text{kg}$) revolves around the sun with an angular velocity of $2 \cdot 10^{-7} \, \text{rad/s}$ in circular orbit of radius $1.5 \cdot 10^{8} \, \text{km}$. The force exerted by the sun on earth in newtons is...

Let check the dimension.

$$[F] = kg \cdot \left(\frac{rad}{s^2}\right) \cdot m = kg \cdot \frac{m}{s^2} = N.$$

Let evaluate the quantity.

$$F = 6 \cdot 10^{24} \cdot \left(2 \cdot 10^{-7}\right)^2 \cdot 1.5 \cdot 10^{11} = 3.6 \cdot 10^{22} \, (N).$$

Answer: $3.6 \cdot 10^{22} \, N$.