Question #36816

A grenade having mass of 10kg flying horizontally with velocity of 10 m/s into two fragment .The larger fragment has velocity of 25 m/s in the direction of the grenade .the smaller fragment has velocity of 12.5 m/s in the opposite direction.the masses of the fragments are ??????????????????????????????????????????????????????????

Expert's answer

A grenade having mass of 10kg10\mathrm{kg} flying horizontally with velocity of 10 m/s10~\mathrm{m/s} into two fragments. The larger fragment has velocity of 25 m/s25~\mathrm{m/s} in the direction of the grenade. the smaller fragment has velocity of 12.5 m/s12.5~\mathrm{m/s} in the opposite direction. The masses of the fragments are?

The law of conservation of momentum:


Mv0=m1v1+m2v2M v _ {0} = m _ {1} v _ {1} + m _ {2} v _ {2}


Sum of mass of fragments equals:


M=m1+m2M = m _ {1} + m _ {2}


From second: m1=Mm2m_{1} = M - m_{2}, substitute to first:


Mv0=(Mm2)v1+m2v2M v _ {0} = (M - m _ {2}) v _ {1} + m _ {2} v _ {2}m2=Mv0v1v2v1=10251025(12.5)kg=4kgm _ {2} = M \frac {v _ {0} - v _ {1}}{v _ {2} - v _ {1}} = 1 0 \frac {2 5 - 1 0}{2 5 - (- 1 2 . 5)} k g = 4 k g


And


m1=Mm2=MMv0v1v2v1=Mv2v0v2v1=1012.51012.525=6kgm _ {1} = M - m _ {2} = M - M \frac {v _ {0} - v _ {1}}{v _ {2} - v _ {1}} = M \frac {v _ {2} - v _ {0}}{v _ {2} - v _ {1}} = 1 0 \frac {- 1 2 . 5 - 1 0}{- 1 2 . 5 - 2 5} = 6 k g


Answer: 6 and 4kg4\mathrm{kg}

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