A grenade having mass of 10kg flying horizontally with velocity of 10 m/s into two fragments. The larger fragment has velocity of 25 m/s in the direction of the grenade. the smaller fragment has velocity of 12.5 m/s in the opposite direction. The masses of the fragments are?
The law of conservation of momentum:
Mv0=m1v1+m2v2
Sum of mass of fragments equals:
M=m1+m2
From second: m1=M−m2, substitute to first:
Mv0=(M−m2)v1+m2v2m2=Mv2−v1v0−v1=1025−(−12.5)25−10kg=4kg
And
m1=M−m2=M−Mv2−v1v0−v1=Mv2−v1v2−v0=10−12.5−25−12.5−10=6kg
Answer: 6 and 4kg