Question #36815

a 10 kg object is subjected to two forces F,one vector = 16 icap - 11j cap and F,two vector = 8i cap + 18 j cap ,the magnitude of resultant acceleration in ms / square will be ?????????????????????????

Expert's answer

Question 36815

We are given force vectors F1(16,11)\vec{F}_1(16, -11) and F2(8,18)\vec{F}_2(8, 18) . The net (resultant) force is F(24,7)\vec{F}(24, 7) . The magnitude of this force is F=242+72=25NF = \sqrt{24^2 + 7^2} = 25N . Hence, according to 2nd2^{\text{nd}} Newtons law, magnitude of acceleration is a=Fm=25N10kg=2.5ms2a = \frac{F}{m} = \frac{25N}{10kg} = 2.5\frac{m}{s^2} .


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