Question

A weightlifter lifts a set of weights a vertical distance of 2.00 m. If a constant net force of 350 N is exerted on the weights, what is the net work done on the weights?

Answer 1

A weightlifter lifts a set of weights a vertical distance of $2.00\mathrm{m}$. If a constant net force of $350\mathrm{N}$ is exerted on the weights, what is the net work done on the weights?

**Solution:**

$$\mathrm{d} = 2.00\mathrm{m} - \text{vertical distance};$$ $$\mathrm{F} = 250\mathrm{N} - \text{net force};$$

The work done by a constant force of magnitude F on a point that moves a displacement d in the direction of the force is the product

$$W = F \cdot d = 2\mathrm{m} \cdot 250\mathrm{N} = 500\mathrm{J}$$

Answer: net work done on the weights is 500J.