Question

A frog falls from a rain forest tree. If we ignore wind resistance how much time does it take the frog to fall a distance of 12 meters?

Answer 1

Question 36376

Frog falls a distance $12m$. Since it has no initial velocity, the law of motion for vertical position of frog is $y(t) = y_0 - \frac{gt^2}{2}$. Hence, for distance $y_0 - y = 12m$, $t = \sqrt{\frac{2 \cdot 12m}{9.81 \frac{m}{s^2}}} = 1.56s$ - this is the time for falling $12m$.