if the hitting is fully unelastic, find the velocity of A and B after hitting.What is the direction that A+B moves after hitting.
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Expert's answer
2011-07-14T06:34:35-0400
We should add the& vectors& of impulse A and B Pa = MaVa = 8*10 = 80 kg*m/s (to the East) Pb = MbVb& = 5*20 = 100 kg m/s (to the North)
The modulus of the impulse after inelastic hitting is radic; (Pa2 + Pb2) = raidc; (802 + 1002) = 128.1 kg m/s The speed : 128.1 / (8 + 5) = 9.85 m/s tan (angle to the North) = 80/100 = 0.8 38.66 degrees from North to East.
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You are welcome!
Thank you so much for helping me...And I'm really sorry for my bad English..
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