Question

A car is rounding an unbanked circular turn with a speed of v = 35 m/s. The radius of the turn is r = 1500 m. What is the magnitude ac of the car’s centripetal acceleration?




0.82 m/s2


1.8 × 106 m/s2


0.023 m/s2


5.4 × 10-4 m/s

Answer 1

A car is rounding an unbanked circular turn with a speed of $\mathrm{v} = 35 \, \mathrm{m/s}$. The radius of the turn is $r = 1500 \, \mathrm{m}$. What is the magnitude ac of the car's centripetal acceleration? $0.82 \, \mathrm{m/s}^2$, $1.8 \times 106 \, \mathrm{m/s}^2$, $0.023 \, \mathrm{m/s}^2$, $5.4 \times 10^{-4} \, \mathrm{m/s}$.

Solution

The magnitude $a_{c}$ of the car's centripetal acceleration be given by formula:

$$a_{c} = \frac{v^{2}}{r},$$

where $v$ - a speed of a car, $r$ - the radius of the turn.

Let's find $a_{c}$:

$$a_{c} = \frac{\left(35 \frac{\mathrm{m}}{\mathrm{s}}\right)^{2}}{1500 \, \mathrm{m}} = 0.82 \frac{\mathrm{m}}{\mathrm{s}^{2}}.$$

Answer: $0.82 \frac{\mathrm{m}}{\mathrm{s}^{2}}$