Question

Every Morning a student jogs around 200m track four times in 30mins. What is the students:
Average speed and Average velocity? show me a solution.

Answer 1

Every Morning a student jogs around 200m track four times in 30mins.

What is the students:

Average speed and Average velocity? Show me a solution.

Solution

A student jogs around 200m track four times, so she pass the distance:

$$S = 4 * 200 \, m = 800 \, m.$$

Average speed of the student:

$$v = \frac{S}{t} = \frac{800 \, m}{30 \, \min} = \frac{800 \, m}{30 * 60 \, s} = 0.44 \, \frac{m}{s}.$$

Average velocity is a vector equal:

$$\vec{v} = \frac{\vec{s}}{t},$$

where $\vec{s}$ – the displacement of the student, $t$ – time of jogging.

The displacement of the student is zero because she jogs around a track four times and returns to her initial position.

Average velocity of the student:

$$\vec{v} = \frac{0}{30 \, \min} = 0.$$

Answer: $0.44 \, \frac{m}{s}$; 0.