a man moves in an open field such that after moving 10m on a straight line , he makes a sharp turn of 60 degree to his left . the total displacement after 8 such turn is equal to ??????????????
1
Expert's answer
2013-10-16T08:14:19-0400
If man only makes 8 turns (he does not move on the straight line) then he consequently makes a sharp turn of 180 degrees to his left.
since he takes a sharp turn of 60 degrees to left he makes an an angle
of 120 degress to the inside,and 60 degrees to the outside.thus it
will form a polygon with mease of interior angle 120 and exterior
angle 60.thus it is a hexagon.thus 6 side after 6th turn it will
complete 2 more turn spanning 2 more side of the hexagon.thus distance
covered will be 20.but displace ment is asked,so we form a trianglr
with 2 sides measuring 10 m and the angle between them is 120.thus by
sin rule of triangle: root3 * side
Leave a comment
Thank you! Your comments have been successfully added. However, they need to be checked by the moderator before being published.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
since he takes a sharp turn of 60 degrees to left he makes an an angle of 120 degress to the inside,and 60 degrees to the outside.thus it will form a polygon with mease of interior angle 120 and exterior angle 60.thus it is a hexagon.thus 6 side after 6th turn it will complete 2 more turn spanning 2 more side of the hexagon.thus distance covered will be 20.but displace ment is asked,so we form a trianglr with 2 sides measuring 10 m and the angle between them is 120.thus by sin rule of triangle: root3 * side
Leave a comment