Question #35529

A person whose mass is m = 70.0 kg steps on a mechanical bathroom scale placed on an inclined plane that makes the angle α = 12.9° with the horizontal. What is the reading on the scale?

Expert's answer

A person whose mass is m=70.0kgm = 70.0 \, \text{kg} steps on a mechanical bathroom scale placed on an inclined plane that makes the angle α=12.9\alpha = 12.9{}^\circ with the horizontal. What is the reading on the scale?

**Solution:**

m=70.0kgm = 70.0 \, \text{kg} - mass of the person;

α=12.9\alpha = 12.9{}^{\circ} - angle which plane makes with the horizontal;

N - reaction force;

M - mass of the person which shows the scales.

Newton's second law for person (the first law of equilibrium):


mg+N+Pfriction=0\overrightarrow{\mathrm{mg}} + \overrightarrow{\mathrm{N}} + \overrightarrow{\mathrm{P}}_{\text{friction}} = \overrightarrow{0}y:Nmgy=0y: N - m g_y = 0


From the a right triangle:


cosα=mgmgy\cos \alpha = \frac{m g}{m g_y}mgy=mgcosαm g_y = m g \cdot \cos \alpha


(2)in(1):


N=mgy=mgcosαN = m g_y = m g \cdot \cos \alpha


Newton's third law: When person exerts a force on a plane, the plane simultaneously exerts a force equal in magnitude and opposite in direction to that of the person:


N=P\overrightarrow{\mathrm{N}} = - \overrightarrow{\mathrm{P}}N=PN = PP=MgP = M g


(5)and(3)in(4):


mgcosα=Mgm g \cdot \cos \alpha = M gM=mcosα=70kgcos12.9=68.23kgM = m \cdot \cos \alpha = 70 \, \text{kg} \cdot \cos 12.9{}^{\circ} = 68.23 \, \text{kg}


Answer: the reading on the scale is 68.23kg68.23 \, \text{kg}

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