Question #35436

a car is driven east for a distance of 50km,then in a direction 30 degrees east of north for 25km.sketch the vector diagram and determine
(a) the magnitude and (b) the angle of the total displacement from its starting point.

Expert's answer


a)


S=A+BS=A2+B22ABcos(90+30)=502+25222550cos(90+30)=66km\begin{array}{l} \vec {S} = \vec {A} + \vec {B} \quad S = \sqrt {A ^ {2} + B ^ {2} - 2 A B \cos (9 0 {}^ {\circ} + 3 0 {}^ {\circ})} \\ = \sqrt {5 0 ^ {2} + 2 5 ^ {2} - 2 * 2 5 * 5 0 \cos (9 0 {}^ {\circ} + 3 0 {}^ {\circ})} = 6 6 \mathrm {k m} \\ \end{array}


b)


B2=A2+S22AScosθB ^ {2} = A ^ {2} + S ^ {2} - 2 A S \cos \thetacosθ=A2+S2B22AS=502+66225225066=0,944θ=20\cos \theta = \frac {A ^ {2} + S ^ {2} - B ^ {2}}{2 A S} = \frac {5 0 ^ {2} + 6 6 ^ {2} - 2 5 ^ {2}}{2 * 5 0 * 6 6} = 0, 9 4 4 \quad \rightarrow \theta = 2 0 {}^ {\circ}

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