Question

An elevator is moving at 1.5 m/s as it approaches its destination floor from below. When the elevator is a distance h from its destination, it accelerates with
a = −0.68 m/s2,
where the negative sign indicates a downward vertical direction. ("Up" is positive.) Find h.

Answer 1

h=V0t-(at^2)/2; V=V0+at
h=1.65 meters