Question #35073

the board is pivoted at f and a steel spring s holds the board in a horizontal position the diver weighs 640N and stands still with gravity directly above a point 1.8M from F as shown calculate the moment of the weight of the diver

Expert's answer

the board is pivoted at f and a steel spring s holds the board in a horizontal position the diver weighs 640N and stands still with gravity directly above a point 1.8M from F as shown calculate the moment of the weight of the diver

**Solution:**

Moment of the weight of the diver is defined as the product of the lever-arm distance d and weight force:


M=Fd=640N1.8m=1152NmM = F \cdot d = 640N \cdot 1.8m = 1152N \cdot m


**Answer:** moment of the weight of the diver is M=1152NmM = 1152N \cdot m

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