Question #350450

2. A car travels form rest and has a constant acceleration of 3 ft/s^2. Find the average velocity during the first 10s of motion.

1
Expert's answer
2022-06-13T15:34:13-0400

Given:

a=3ft/s2a=3\:\rm ft/s^2

v0=0ft/sv_0=0\:\rm ft/s

t=10st=10\:\rm s


The distance traveled by a car during the first 10s of motion

d=v0t+at2/2=3102/2=150  ftd=v_0t+at^2/2=3*10^2/2=150\;\rm ft

The average velocity during this period of motion

vave=dt=15010=15ft/sv_{ave}=\frac{d}{t}=\frac{150}{10}=15\:\rm ft/s


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