Question

Q.A car travelling at 60 km/hr overtakes another car travelling at 42 km/hr. Assuming the car to be 5 m long, the total road distance used for the overtake?

Answer 1

$$2S = \Delta v * t$$ $$S = 5m$$ $$\Delta v = (60 - 48)km / hr = 18km / hr$$ $$t = \frac{2S}{\Delta v} = \frac{1}{18} 10^{-2} hr$$ $$L = 5 + 60 * t = 0.038km$$