Question #34953

I really need a huge help for this physics homework.. please can you answer this for me ? Thank you so much . the problem runs this way:

A 40 kilogram mass is pulled by a 80 newton force which is 30 degrees from the horizontal along a level floor. What is the work done by the 80 newton force after travelling 15 meters?

Expert's answer

A 40 kilogram mass is pulled by an 80 newton force which is 30 degrees from the horizontal along a level floor. What is the work done by the 80 newton force after travelling 15 meters?

Mathematically, work can be expressed by the following equation:


W=FdcosθW = F d \cos \theta


where FF is the force, dd is the displacement, and the angle θ\theta is defined as the angle between the force and the displacement vector.



In this case θ=30\theta = 30{}^{\circ}, therefore:


W=80N15mcos30=6003J1040JW = 80 N * 15 m * \cos 30{}^{\circ} = 600 \sqrt{3} \, J \approx 1040 J


Answer: W=1040JW = 1040 \, J

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