Question #344595

Given r1=3mi+4mj.dertemine the magnitude and direction angles of the position vector

1
Expert's answer
2022-05-25T10:27:04-0400
r=(3i^+4j^)m\vec r=(3\hat i+4\hat j)\:\rm m

The magnitude

r=32+42=5  mr=\sqrt{3^2+4^2}=5\;\rm m

The direction angles

α=cos135=53\alpha=\cos^{-1}\frac{3}{5}=53^\circ

β=cos145=37\beta=\cos^{-1}\frac{4}{5}=37^\circ


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