Question

A body of mass 4 kg, projected at an angle of 65° from the ground with an initial velocity of 36 m/s, acceleration due to gravity is g = 9.81 m/s², determine:

a) time of flight 

b) maximum horizontal distance covered 

c) maximum vertical distance covered 

Answer 1

$t=\frac{2v\sin\alpha}g=6.65~s,$

$s=\frac{v\sin 2\alpha}g=101.2~m,$

$h=\frac{v^2\sin^2\alpha}{2g}=54.3~m.$