Question

a batsman deflect a ball by an angle of 45 degree without changing its initial speed which is equal to 54km/hour mass of a ball is 0.15kg .what is the impulse imparted to the ball

Answer 1

We transform speed from km/hour to m/s:

$$V = 54 \frac {km}{hour} = \frac {54000}{3600} = 15 \frac {m}{s}$$

Momentum is:

$$p = mV$$

Find the first momentum:

$$p _ {1} = m V = 0.15 \cdot 15 = 2.25 \, kg \cdot \frac {m}{s}$$

After occasion we have the second momentum:

$$p _ {2} = m V \cdot \cos (45{}^{\circ}) = 0.15 \cdot 15 \cdot 0.7 = 1.575 \, kg \cdot \frac {m}{s}$$

In projection on $X$:

$$p _ {1} = - 2.25 \, kg \cdot \frac {m}{s}$$ $$p _ {2} = 1.575 \, kg \cdot \frac {m}{s}$$ $$\Delta p = p _ {2} - p _ {1} = 3.825 \, kg \cdot \frac {m}{s}$$