Question

A man starts with an initial velocity of 3.50 m/s and accelerates for a distance of 205 m over 28.7s. What is the acceleration of the man?

Answer 1

$s=vt+\frac{at^2}2,$

$a=\frac{2s}{t^2}-\frac{2 v}t=0.25~\frac m{s^2}.$