Answer to Question #341837 in Mechanics | Relativity for Cassidy54

Mechanics | Relativity

Question #341837

A man starts with an initial velocity of 3.50 m/s and accelerates for a distance of 205 m over 28.7s. What is the acceleration of the man?

Expert's answer

"s=vt+\\frac{at^2}2,"

"a=\\frac{2s}{t^2}-\\frac{2 v}t=0.25~\\frac m{s^2}."

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