The length of a wire is a metre when the tension is 4N, Length is b metre when the tension is 5N, What is the length when the tension is 9N?
Solution
Using Hooks law:
4=k∗(a−l);5=k∗(b−l);9=k∗(c−l);
Where l – initial length, c – length when the tension is 9N, k – elastic coefficient.
From (1) and (2) we will find initial length and elastic coefficient:
K=(a−l)4;5=(a−l)4∗(b−l);5∗(a−l)=4∗(b−l);5∗a−4∗b=l;
Let's substitute (5) into (4):
K=(a−5∗a+4∗b)4=(b−a)1;
Let's substitute (6) and (5) into (3):
9=(b−a)1∗(c−5∗a+4∗b);9∗b−9∗a=c−5∗a+4∗b;5∗b−4∗a=c;
Answer: the length when the tension is 9N is (5∗b−4∗a)m.