Question

a crickt bal z thrown at an angle 30degre with verticle at a sped of 10m/s.calcult the max.height,range n time taken to come the same lavel

Answer 1

V – speed, t – time, 60 deg with horizont('cause 90-30=60 deg)

$$H_{max} = \frac{V^{2} \sin 60{}^{\circ 2}}{2g}$$ $$H_{max} = \frac{100 \cdot 0.86 \cdot 0.86}{20} = 3.69 \text{ meters}$$ $$t = \frac{2V \cos 60{}^{\circ}}{g}$$ $$t = \frac{20 \cdot 0.5}{10} = 1 \text{ sec}$$