Question

A flat, circular metal disk of uniform thickness has a radius of 3.20 cm. A hole is drilled in the disk that is 1.60 cm in radius. The hole is tangent to one side of the disk. Where r = 3.20.Where is the x-component of the CM of the disk now that the hole has been drilled? 

 

Answer 1

$r_x=(1-\sqrt 2)r=-1.33~cm.$