Question #33991

Find the force applied on a 10Kg body downward with an acceleration of 3 taking the value of gravity 10?

Expert's answer

Find the force applied on a 10Kg body downward with an acceleration of 3 taking the value of gravity 10?

!!! Necessary to clarify the condition of the problem.

1. The body falls to the acceleration of 3 m/s2

2. The body falls to the acceleration and = 3g

Solution1:

Let mb=10kg;a=3ms2;g=10ms2m_b = 10\,kg; a = 3\,\frac{m}{s^2}; \quad g = 10\,\frac{m}{s^2}


Solution 2

Let mb=10kg;a=3g=30ms2;g=10ms2m_b = 10\,kg; a = 3g = 30\,\frac{m}{s^2}; \quad g = 10\,\frac{m}{s^2}

Newton's second low in our case:


F+mg=maF=m(ga)=10(103)=700N-F + mg = ma \rightarrow F = m(g - a) = 10(10 - 3) = 700\,N


I suppose this is body fall in the air and F – force of the air resistance.

Answer 700N

Newton's second low in our case:


F+mg=maF=m(ag)=10(3010)=200NF + mg = ma \rightarrow F = m(a - g) = 10(30 - 10) = 200\,N


Answer: 200N


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