Find the force applied on a 10Kg body downward with an acceleration of 3 taking the value of gravity 10?
!!! Necessary to clarify the condition of the problem.
1. The body falls to the acceleration of 3 m/s2
2. The body falls to the acceleration and = 3g
Solution1:
Let mb=10kg;a=3s2m;g=10s2m

Solution 2
Let mb=10kg;a=3g=30s2m;g=10s2m
Newton's second low in our case:
−F+mg=ma→F=m(g−a)=10(10−3)=700N
I suppose this is body fall in the air and F – force of the air resistance.
Answer 700N
Newton's second low in our case:
F+mg=ma→F=m(a−g)=10(30−10)=200N
Answer: 200N
