Question #33907

A body of mass m resting on a wedge of angle а.Given acceleration f.What is the value of f to set free the mass from inclind plane?

Expert's answer

A body of mass m resting on a wedge of angle a. Given acceleration f. What is the value of f to set free the mass from inclined plane?

Solution:

Condition of the problem does not say the direction of acceleration f\vec{f} , so let it be directed perpendicular to the inclined plane.

At the time of separation from the inclined plane reaction force Nr\overrightarrow{N_r} is equal to zero (the object does not touch the wedge):



Newton's second law: F+mg+Nr+Ffriction=0\vec{F} +\overrightarrow{mg} +\overrightarrow{N_r} +\overrightarrow{F_{friction}} = \vec{0}

y:(mg)yF=0y: (m g) _ {y} - F = 0(mg)y=mgcosa(m g) _ {y} = m g \cdot \cos a \rightarrowy:mgcosaF=0(1)y: m g \cdot \cos a - F = 0 (1)F=mf(2) (Newton’s second law)F = m f (2) \text{ (Newton's second law)}mgcosamf=0m g \cdot \cos a - m f = 0f=gcosa=9.8ms2cosaf = g \cdot \cos a = 9.8 \frac{m}{s^{2}} \cos a


Answer: f=9.8ms2cosaf = 9.8 \frac{m}{s^2} \cos a

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