A body of mass m resting on a wedge of angle a. Given acceleration f. What is the value of f to set free the mass from inclined plane?
Solution:
Condition of the problem does not say the direction of acceleration f , so let it be directed perpendicular to the inclined plane.
At the time of separation from the inclined plane reaction force Nr is equal to zero (the object does not touch the wedge):

Newton's second law: F+mg+Nr+Ffriction=0
y:(mg)y−F=0(mg)y=mg⋅cosa→y:mg⋅cosa−F=0(1)F=mf(2) (Newton’s second law)mg⋅cosa−mf=0f=g⋅cosa=9.8s2mcosa
Answer: f=9.8s2mcosa