Question

a plane flying horizontally at 100 m/s at a height of 1000 m releases a bomb. find
i) the time taken to reach the ground.
ii) the distance of the target

Answer 1

a plane flying horizontally at $100\mathrm{m / s}$ at a height of $1000\mathrm{m}$ releases a bomb. find

i) the time taken to reach the ground.

ii) the distance of the target

Solution:

After releasing, the bomb has the same speed as the plane. The equation of motion of the bomb to Y-axis: (t - time taken to reach the ground)

$$H = \frac {g t ^ {2}}{2}$$ $$\begin{array}{l} t = \sqrt {\frac {2 H}{g}} = \sqrt {\frac {2 \cdot 1 0 0 0 m}{9 . 8 \frac {m}{s ^ {2}}}} \\ = 1 4. 2 8 s (1) \\ \end{array}$$

The equation of motion of the bomb to X-axis: (D- distance of the target)

$$\begin{array}{l} D = V t (2) \\ (1) t o (2): D = 1 0 0 \frac {m}{s} \cdot 1 4. 2 8 s \\ = 1 4 2 8 m \\ \end{array}$$

Answer: 1) - time taken to reach the ground $t = 14.28s$

2) distance of the target $D = 1428m$