Question

A projectile is fired in a way that its horizontal range is equal to three times its maximum height .What is the angle of projection?

Answer 1

$$R=3H$$

$$\frac{v_0^2\sin2\theta}{g}=3\frac{v_0^2\sin^2\theta}{2g}$$

$$\tan\theta=\frac{2}{3}$$

$$\theta=33.4^\circ$$